For MySql

Let us assume a Customers table with a CustomerName Column which contain string of Max Length 200.

//Column data

+-----+---------------------------------------------+
| id  | CustomerName                                |
+-----+---------------------------------------------+
| 1   | Alfreds Futterkiste                         |
| 2   | Ana Trujillo Emparedados y helados          |
| 3   | Antonio Moreno Taquería                     |
| 4   | Around the Horn                             |
| 5   | Berglunds snabbköp                          |
| 6   | Blauer See Delikatessen                     |
| 7   | Blondel père et fils                        |
| 8   | Bólido Comidas preparadas                   |
+-----+---------------------------------------------+

SELECT
  CONCAT (
    SUBSTR(`Customers`.`CustomerName`, 1, 15),
    IF(
      LENGTH(`Customers`.`CustomerName`) > 15,
      '...',
      ''
    )
  ) as `name`
FROM
  `Customers`;

//output

+-----+---------------------------------------------+
| id  | CustomerName                                |
+-----+---------------------------------------------+
| 1   | Alfreds Futterk...                          |
| 2   | Ana Trujillo Em...                          |
| 3   | Antonio Moreno ...                          |
| 4   | Around the Horn                             |
| 5   | Berglunds snabb...                          |
| 6   | Blauer See Deli...                          |
| 7   | Blondel père et...                          |
| 8   | Bólido Comidas ...                          |
+-----+---------------------------------------------+

For Sql Server

Let us assume a Customers table with a CustomerName Column which contain string of Max Length 200.

//Column data

+-----+---------------------------------------------+
| id  | CustomerName                                |
+-----+---------------------------------------------+
| 1   | Alfreds Futterkiste                         |
| 2   | Ana Trujillo Emparedados y helados          |
| 3   | Antonio Moreno Taquería                     |
| 4   | Around the Horn                             |
| 5   | Berglunds snabbköp                          |
| 6   | Blauer See Delikatessen                     |
| 7   | Blondel père et fils                        |
| 8   | Bólido Comidas preparadas                   |
+-----+---------------------------------------------+

SELECT
  SUBSTRING(CustomerName, 1, 15) + (
    CASE WHEN LEN(CustomerName) > 15 THEN '...' ELSE '' END
  )
FROM
  Customers;

//output

+-----+---------------------------------------------+
| id  | CustomerName                                |
+-----+---------------------------------------------+
| 1   | Alfreds Futterk...                          |
| 2   | Ana Trujillo Em...                          |
| 3   | Antonio Moreno ...                          |
| 4   | Around the Horn                             |
| 5   | Berglunds snabb...                          |
| 6   | Blauer See Deli...                          |
| 7   | Blondel père et...                          |
| 8   | Bólido Comidas ...                          |
+-----+---------------------------------------------+

The post Get a string after a specific substring by length in MySQl and SQL appeared first on MaXEster Technologies | Technical Blog.

In this below query, the user table is used and there is 2 latitude and longitude. One is for the user and we will get it from the user and others commented we need to pass to fetch data of users as per that particular area.

SELECT
  `users`.id,
  (
    3959 * acos(
      cos(radians('--Here--')) * cos(radians(`users`.latitude)) * cos(
        radians(`users`.longitude) - radians(--Longitude Here--)
      ) + sin(radians(--Latitude Here--)) * sin(radians(`users`.latitude))
    )
  ) AS distance
FROM
  `users`
HAVING
  `distance` < 10
ORDER BY
  `distance` ASC
LIMIT
  50
LIMIT 50

In which limit also used. If you also want to use that’s ok if you not want limit you can remove that limit code to fetch all data. Also in this, we have used the order by distance so the nearby user’s data comes first and then far users.

The post Find users within a distance by using Latitude, Longitude, and MySQL appeared first on MaXEster Technologies | Technical Blog.

Let us assume a table with three column called cert1, cer2 and cert3

First we need to select the column with a desired name and then Union all of them together with common name selected.

$union1 = Info::whereNotNull('cert1')
->select('cert1 AS Certificate ')
->Where('cert1', 'like', $request->input('term') . '%');

$union2 = Info::whereNotNull('cert2'
)->select('cert2 AS Certificate ')
->Where('cert2', 'like', $request->input('term') . '%');

$union = Info::whereNotNull('cert3')
->select('cert3 AS Certificate ')
->Where('cert3', 'like', $request->input('term') . '%')
->union($union2)
->union($union1)
->groupby('union')->get();

Here Certificate is the common selected.

To write the same query in sql:-

SELECT a.`cert1` as Certificate FROM info as a 
UNION 
SELECT b.`cert2` as Certificate FROM info as b 
UNION 
SELECT c.`cert3` as Certificate FROM info as c

The post How To Select Different Column of data as one with Laravel and MySql? appeared first on MaXEster Technologies | Technical Blog.